JEE Advanced | 2014Trigonometric EquationHard
Question
The following integral 
(2 cosec x)17 dx is equal to
(2 cosec x)17 dx is equal toOptions
A.
2(eu + e-u)16du
2(eu + e-u)16duB. (eu + e-u)17du
(eu + e-u)17duC. (eu - e-u)17du
(eu - e-u)17duD. 2(eu - e-u)16du
2(eu - e-u)16duSolution
I = 
(2 cosec x)17 dx
=
cosec x + cot x + 
. 2cosec xdx
Let cosecx + cotx = eu
⇒ - cosecxdx = du
⇒ I = - 2
(eu + e-u)16du = 
2(eu + e-u)16 du
(2 cosec x)17 dx=
cosec x + cot x + . 2cosec xdxLet cosecx + cotx = eu
⇒ - cosecxdx = du
⇒ I = - 2
(eu + e-u)16du = 2(eu + e-u)16 duCreate a free account to view solution
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