Trigonometric EquationVery Hard
Question
Match List-I with List-II and select the correct answer using the code given below the lists.
Options
A.P → 4, Q → 3, R → 1, S → 2
B.P → 4, Q → 3, R → 2, S → 1
C.P → 3, Q → 4, R → 2, S → 1
D.P → 3, Q → 4, R → 1, S → 2
Solution
(P)
(Q)
A(cosx, sinx), B(cosy, siny) & C(cosz, sinz) lie on circle x2 + y2 = 1
∴ (0,0) is circumcentre as well as centroid of ᐃABC
⇒ ᐃABC is an equilateral triangle
(R)
= sin 2x (1- tan x)
√2 sin x cos2x = sin 2x (1- tan x)
sin x(√2 cos2x - 2 (sin x - cos x)) = 0
⇒ sin x = 0 or sin x = cos x or sin x + cos x = √2
⇒ secx =
1 or sec x 
(S)
⇒ 1 - 6x2 = 6 + 6x2
⇒
(Q)
A(cosx, sinx), B(cosy, siny) & C(cosz, sinz) lie on circle x2 + y2 = 1
∴ (0,0) is circumcentre as well as centroid of ᐃABC
⇒ ᐃABC is an equilateral triangle
(R)
= sin 2x (1- tan x)√2 sin x cos2x = sin 2x (1- tan x)
sin x(√2 cos2x - 2 (sin x - cos x)) = 0
⇒ sin x = 0 or sin x = cos x or sin x + cos x = √2
⇒ secx =
1 or sec x (S)
⇒ 1 - 6x2 = 6 + 6x2
⇒
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