Mole ConceptMedium
Question
To neutralize completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3PO3), the volume of 0.1 M aqueous KOH solution required is
Options
A.10 mL
B.60 mL
C.40 mL
D.20 mL
Solution
No. of gm equivalents of phosphorous acid
= No. of gm equivalents of KOH
20 × 0.1 × 2 (n = factor) = 0.1 × V
= 0.1 × V
V =
= 40 ml
= No. of gm equivalents of KOH
20 × 0.1 × 2 (n = factor) = 0.1 × V
= 0.1 × V
V =
= 40 mlCreate a free account to view solution
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