Work, Power and EnergyHard
Question
A spring of spring constant 5 × 103 N/m is stretched initially by 5 cm from the unstretched position. Then the work required to stretch is further by another 5 cm is
Options
A.12.50 N-m
B.18.75 N-m
C.25.00 N-m
D.6.25 N-m
Solution
Required work done = 25 - 6.25 = 18.75 N-m.
Create a free account to view solution
View Solution FreeMore Work, Power and Energy Questions
A spring of force constant 800 N/m has an extension of 5 cm. The work done is extending it from 5 cm to 15 cm is...The kinetic energy of a body becomes four times its initial value. The new linear momentum will be:-...Position of a particle of mass 2 kg is given by x = + t2, then what will be the work done in first two seconds :-...If the momentum of a body is increased by 100%, then the percentage increase in the kinetic energy is :-...Consider two process A and B on a system as shown in the figure let ᐃW1 and ᐃW2 be the work done by the syst...