Nuclear Physics and RadioactivityEasy
Question
A nucleus with Z = 92 emits the following in a sequence; α, α, β-, β-, α, α, α, α, β-, β-, α, β+, β+, α. The Z of the resulting nucleus is
Options
A.76
B.78
C.82
D.74
Solution
The Z of resultant nucleus = 92 - 16 + 4 - 2 = 78
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