GravitationMedium
Question
The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become
Options
A.10 hours
B.80 hours
C.40 hours
D.20 hours
Solution
Time period of a satellite T = 
r = distance between satellite and the earth.
T ∝ r3/2
⇒
T2 = 8T1 = 8 × 5 = 40 hours
r = distance between satellite and the earth.
T ∝ r3/2
⇒
T2 = 8T1 = 8 × 5 = 40 hours
Create a free account to view solution
View Solution FreeMore Gravitation Questions
The radius of earth is about 6400 km and that of mass is about 3200km. The mass of the earth is about 10 times of the ma...If g is the acceleration due to gravity on the earth′s surface, the gaing in the potential energy of an object mas...A particle of mass 10 g is kept on the surface of a uniform sphere of mass 100 kg and radius 10 cm. Find the work to be ...The kinetic energy needed to project a body of mass m from the earth surface (radius R) to infinity is...The dependence of acceleration due to gravity g on the distance r from the centre of the earth, assumed to be a sphere o...