Current Electricity and Electrical InstrumentHard
Question
The resistance of the series combination of two resistances is S. When they are joined in parallel through total resistance is P. If S = nP, then the minimum possible value of n is
Options
A.4
B.3
C.2
D.1
Solution
Let resistances be R1 and R2
So, S = R1 + R2;
P =
S = nP
R1 + R2 =
(R1 + R2)2 = nR1R2
If R1 = R2, so minimum value of n = 4.
So, S = R1 + R2;
P =
S = nP
R1 + R2 =
(R1 + R2)2 = nR1R2
If R1 = R2, so minimum value of n = 4.
Create a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
Find the resistance of a wire frame shaped as a cube (figure) when measured between points 1-7...-...Equivalent resistance of series combination -...Four resistances are connected in a circuit as shown in the following diagram.The value of the current in ampere in 4 oh...The effective resistance between points P and Q of the electrical circuit shown in the figure is...