Wave OpticsHard
Question
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young′s double-slit experiment is
Options
A.infinite
B.five
C.three
D.zero
Solution
For interference maxima, d sin θ = nλ
Here d = 2λ
∴ sin θ = n/2 and is satisfied by 5 integral values of n (-2, -1, 0, 1, 2), as the maximum value of sin θ can only be 1.
Here d = 2λ
∴ sin θ = n/2 and is satisfied by 5 integral values of n (-2, -1, 0, 1, 2), as the maximum value of sin θ can only be 1.
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