Geometrical OpticsHard
Question
The magnifying power of a telescope is 9. When it is adjusted for parallel rays the distance between the objective and eyepiece is 20 cm. The focal length of lenses are
Options
A.11 cm, 9 cm
B.10 cm, 10 cm
C.15 cm, 5 cm
D.18 cm, 2 cm
Solution
f0 + fe = 20 ....(i)
....(ii)
Solving F0 = 10 cm
Fe = 2 cm
....(ii)Solving F0 = 10 cm
Fe = 2 cm
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