SHMMedium
Question
A cage of mass M hangs from a light spring of force constant of force constant k. A body of mass m falls height h inside the cage sticks to its floor. The amplitude of oscillations of the cage will be-
Options
A.
B.
C.
D.
Solution
mgh = 
(M + m) v2 = 
kx2
mgh = kx2 x =
(M + m) v2 = kx2mgh = kx2 x =
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