SHMHard
Question
A cage of mass M hangs from a light spring of force constant of force constant k. A body of mass m falls height h inside the cage sticks to its floor. The amplitude of oscillations of the cage will be-
Options
A.
B.
C.
D.
Solution
mgh = 
(M + m) v2 = 
kx2
mgh = kx2 x =
(M + m) v2 = kx2mgh = kx2 x =
Create a free account to view solution
View Solution FreeMore SHM Questions
A simple pendulum of length L has an energy E and amplitude A. The energies of the simple pendulum (i) when the length i...An ideal gas enclosed in a vertical cylindrical container supports a freely moving piston of mass M. The piston and the ...A simple pendulum is suspended from the ceiling of a vehicle, its time period is T. Vehicle is moving with constant velo...The time period of a spring pendulum on earth is T. If it is taken on the moon, and made to oscillate, the period of vib...The equation of motion of a particle of mass 1 g is + π2x = 0 where x is displacement (in m) from mean position. Th...