SHMMedium
Question
A point mass oscillates along the x-axis according to the law x = x0 cos (ωt - π/4). If the acceleration of the particle is written as a = A cos(ωt + δ)
Options
A.A = x0, δ = - π/4
B.A = x0ω2, δ = - π/4
C.A = x0ω2, δ = - π/4
D.A = x0ω2, δ = 3π/4
Solution
V = - x0ω sin (ωt - π/4)
a = - x0ω2 cos
a = A cos(ωt + δ)
A = x0ω2; δ =
a = - x0ω2 cos
a = A cos(ωt + δ)
A = x0ω2; δ =
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