SHMHard
Question
A point mass oscillates along the x-axis according to the law x = x0 cos (ωt - π/4). If the acceleration of the particle is written as a = A cos(ωt + δ)
Options
A.A = x0, δ = - π/4
B.A = x0ω2, δ = - π/4
C.A = x0ω2, δ = - π/4
D.A = x0ω2, δ = 3π/4
Solution
V = - x0ω sin (ωt - π/4)
a = - x0ω2 cos
a = A cos(ωt + δ)
A = x0ω2; δ =
a = - x0ω2 cos
a = A cos(ωt + δ)
A = x0ω2; δ =
Create a free account to view solution
View Solution FreeMore SHM Questions
The time period of a particle exciting SHM is T. after a time T/6 after it passes its :...A particle is dropped from a height equal to the radius of the earth above the tunnel dug through the earth as shown in ...The potential energy of a particle executing S.H.M. at a distance x from mean position is :...If a SHM is given by y = (sin ωt + cos ωt) m, which of the following statements are true?...For a SHM with given angular frequency, two arbitrary initial conditions are necessary and sufficient to determine the m...