SHMHard
Question
The time period of a particle exciting SHM is T. after a time T/6 after it passes its :
Options
A.displacement will be one - half of its amplitude
B.velocity will be one - half of its maximum velocity
C.kinetic energy = 1/3(potential energy)
D.acceleration will be 
times of its maximum acceleration
times of its maximum accelerationSolution
Let x = A sinωt where ω = 
For (A) : At t = x = A sin
= A sin 
A, x = A sin 
= A sin 
For (B) ; v =
= Aωcosω t At t = 
= Aω cos 
For (C) : Ke =
mv2 = 
m 
(KE)max = 
(TE) & PE = TE - KE = 
TE ⇒ KE = 
(PE)
For (D) : Acceleration a =
= - Aω2sin ωt = - ω2x
For (A) : At t = x = A sin
= A sin A, x = A sin = A sin For (B) ; v =
= Aωcosω t At t = = Aω cos For (C) : Ke =
mv2 = m (KE)max = (TE) & PE = TE - KE = TE ⇒ KE = (PE)For (D) : Acceleration a =
= - Aω2sin ωt = - ω2xCreate a free account to view solution
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