SHMMedium
Question
The time period of a particle exciting SHM is T. after a time T/6 after it passes its :
Options
A.displacement will be one - half of its amplitude
B.velocity will be one - half of its maximum velocity
C.kinetic energy = 1/3(potential energy)
D.acceleration will be
times of its maximum acceleration
Solution
Let x = A sinωt where ω = 
For (A) : At t = x = A sin
= A sin
A, x = A sin
= A sin 
For (B) ; v =
= Aωcosω t At t =
= Aω cos 
For (C) : Ke =
mv2 =
m
(KE)max =
(TE) & PE = TE - KE =
TE ⇒ KE =
(PE)
For (D) : Acceleration a =
= - Aω2sin ωt = - ω2x
For (A) : At t = x = A sin
For (B) ; v =
For (C) : Ke =
For (D) : Acceleration a =
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