MatricesEasy
Question
Let A be a square matrix all of whose entries are integers. Then which one of the following is true?
Options
A.If detA = ± 1, then A-1 exists but all its entries are not necessarily integers
B.If detA ≠ ± 1, then A-1 exists and all its entries are non-integers
C.If detA = ± 1, then A-1 exiexists and all its entries are integers
D.If detA = ± 1, then A-1 need not exist
Solution
Each entry of A is integer, so the cofactor of every entry is an integer and hence each entry in the adjoint of matrix A is integer.
Now detA = ± 1 and A-1 =
(adj A)
⇒ all entries in A-1 are integers.
Now detA = ± 1 and A-1 =
(adj A)⇒ all entries in A-1 are integers.
Create a free account to view solution
View Solution FreeMore Matrices Questions
If is the adjoint of a 3 × 3 matrix A and |A| = 4, then α is equal to...Let $P = \left\lbrack p_{ij} \right\rbrack$ and $Q = \left\lbrack q_{ij} \right\rbrack$ be two square matrices of order ...The adjoint of symmetric matrix is -...Let M be a $3 \times 3$ matrix such that$M\begin{pmatrix} 1 \\ 0 \\ 0 \end{pmatrix} = \begin{pmatrix} 1 \\ 2 \\ 3 \end{p...Median and mode of a moderately Skew symmetric distribution is 13 and 7 respectively then mean of the distribution will ...