ThermodynamicsHard
Question
Two moles of helium gas are taken over the cycle ABCDA, as shown in the P - T diagram.
The net work done on the gas in the cycle ABCDA is
The net work done on the gas in the cycle ABCDA is
Options
A.Zero
B.276 R
C.1076 R
D.1904 R
Solution
Net work done in a cycle = WAB + WBC + WCB + WBA
= 400 R + 2 × 2.303 × 500 R ln 2 - 400R - 414 R
= 1000R x ln 2 - 600R x ln 2 = 400R x ln 2 = 276R
= 400 R + 2 × 2.303 × 500 R ln 2 - 400R - 414 R
= 1000R x ln 2 - 600R x ln 2 = 400R x ln 2 = 276R
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