ThermodynamicsHard
Question
Two moles of helium gas are taken over the cycle ABCDA, as shown in the P - T diagram.
The net work done on the gas in the cycle ABCDA is
The net work done on the gas in the cycle ABCDA is
Options
A.Zero
B.276 R
C.1076 R
D.1904 R
Solution
Net work done in a cycle = WAB + WBC + WCB + WBA
= 400 R + 2 × 2.303 × 500 R ln 2 - 400R - 414 R
= 1000R x ln 2 - 600R x ln 2 = 400R x ln 2 = 276R
= 400 R + 2 × 2.303 × 500 R ln 2 - 400R - 414 R
= 1000R x ln 2 - 600R x ln 2 = 400R x ln 2 = 276R
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
Two moles of ideal helium gas are in a rubber balloon at 30oC. The balloon is fully expandable and can be assumed to req...The process of converting solid into directly gaseous state on being heated is called :-...If Cp and Cv denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, ...Two rigid boxes containing different ideal gases are placed on a table. Box A contains one mole of nitrogen at temperatu...p-V plots for two gases during adiabatic processes are shown in the figure. Plots 1 and 2 should correspond respectively...