NEET | 2018Errors in measurementHard
Question
A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular
scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of – 0.004 cm, the correct diameter of the ball is :-
Options
A.
0.521 cm
B.
0.525 cm
C.
0.053 cm
D.
0.529 cm
Solution
Reading of screw gauge
= MSR + VSR × LC + zero error
= 0.5 cm + 25 × 0.001 cm + 0.004 cm
= 0.529 cm
Create a free account to view solution
View Solution FreeMore Errors in measurement Questions
If the percentage error in the measurement of radius of a sphere is 2%, then the maximum percentage errors in the measur...In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division $= 0...The density of a material in the shape of a cube is determined by measuring three sides of the cube and its mass. If the...In an experiment, a set of reading are obtained $- 1.24\text{ }mm,1.25\text{ }mm,1.23\text{ }mm,1.21\text{ }mm$. The exp...In a screw gauge, the zero of the circular scale lies 3 divisions above the horizontal pitch line when their metallic st...