In an experiment the values of two spring constants were measured as $k_{1} = (10 \pm 0.2)N/m$ and $

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In an experiment the values of two spring constants were measured as $k_{1} = (10 \pm 0.2)N/m$ and $k_{2} = (20 \pm 0.3)N/m$. If these springs are connected in parallel, then the percentage error in equivalent spring constant is :

Accepted Answer

For parallel combination of spring,$${K_{eq} = K_{1} + K_{2} = 30	ext{ }N/m }{\Delta K_{eq} = \Delta K_{1} + \Delta K_{2} = 0.2 + 0.3 = 0.5	ext{ }N/m }$$$	herefore\ $ %Error in $K = \frac{0.5}{30} 	imes 100 = 1.67\%$

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