ElectroMagnetic InductionEasy

Question

The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance :-

Options

A.

0.138 H

B.

138.88 H

C.

1.389 H

D.

13.89 H

Solution

PE=12 LI2
25×10-3=12L(60×10-3 )2
L = 13.89 H

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