Work, Power and EnergyHard

Question

A particle is projected along the inner surface of a smooth vertical circle of radius R, its velocity at the lowest being . It will leave the circle at an angular distance .... from the highest point

Options

A.37o
B.53o
C.60o
D.30o

Solution

by conservation of mechanical energy [between point A and B]
mu2 = mg R(1 + cos θ) +mv2
= mg(1 + cosθ) + mgRcosθ
= 2 + 2cos θ + cos θ ⇒ 3cosθ = ⇒ cos θ = ⇒ θ  = 53o

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