Work, Power and EnergyHard
Question
A particle is projected along the inner surface of a smooth vertical circle of radius R, its velocity at the lowest being
. It will leave the circle at an angular distance .... from the highest point
Options
A.37o
B.53o
C.60o
D.30o
Solution
by conservation of mechanical energy [between point A and B]
mu2 = mg R(1 + cos θ) +
mv2
= mg(1 + cosθ) +
mgRcosθ
⇒
= 2 + 2cos θ + cos θ ⇒ 3cosθ =
⇒ cos θ =
⇒ θ = 53o

⇒

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