JEE Advanced | 2018Magnetic field due to currentHard

Question

Two infinitely long straight wires lie in the xy-plane along the lines x = ±R. The wire located at x = +R carries a constant current I1 and the wire located at x = –R carries a constant current I2. A circular loop of radius R is suspended with its centre at (0, 0, 3R ) and in a plane parallel to the xy-plane. This loop carries a constant current I in the clockwise direction as seen from above the loop. The current in the wire is taken to be positive if it is in the + j^direction. Which of the following statements regarding the magnetic field B is (are) true ?

Options

A.

If I1 = I2, then B r cannot be equal to zero at the origin (0, 0, 0)

B.

 If I1 > 0 and I2 < 0, then B can be equal to zero at the origin (0, 0, 0)

C.


If I1 < 0 and I2 > 0, then B can be equal to zero at the origin (0, 0, 0)

D.

If I1 = I2, then the z-component of the magnetic field at the centre of the loop is -μoI2R
 

Solution

(A) At origin, B = 0  due to two wires if I1 = I2, hence(Bnet ) net  at origin is equal to B due to ring, which is non-zero.
(B) If I1 > 0 and I2 < 0,  B at origin due to wires will be along +k^ direction and  B due to ring is along - k^direction and henceB can be zero at origin.
(C) If I1 < 0 and I2 > 0,B  at origin due to wires is along  - k^ and also along - k^due to ring, hence B cannot be zero.
(D)


At centre of ring, Bdue to wires is along x-axis
hence z-component is only because of ring whichB=μoi2R-k^

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