NEET | 2018SHMHard

Question

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s2 at a distance of 5 m from the mean position. The time period of oscillation is :-

Options

A.

2π s

B.

π s

C.

2 s

D.

1 s

Solution

|a| = ω2x
20 = ω25⇒ω2=4 ⇒ω=2⇒2πT=2
T = π sec

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