NEET | 2018Physics miscellaneousHard

Question

A carbon resistor (47 ± 4.7) kΩ is to be marked with rings of different colours for its identification. The colour code sequence will be :-

Options

A.

Violet - Yellow - Orange - Silver

B.

Yellow - Violet - Orange - Silver

C.

Yellow - Green - Violet - Gold

D.

Green - Orange - Violet - Gold

Solution

R=(47±4.7)×103
R=47×103±10%Ω
As per color code, 3 - Orange, 4 - Yellow, 7 - Violet,
10% - Silver

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