JEE Advanced | 2014Current Electricity and Electrical InstrumentHard
Question
Two ideal batteries of emf V1 and V2 and three resistances R1, R2 and R3 are connected as shown in the figure. The current in resistance R2 would be zero if
Options
A.V1 = V2 and R1 = R2 = R3
B.V1 = V2 and R1 = 2R2 = R3
C.V1 = 2V2 and 2R1 = 2R2 = R3
D.2V1 = V2 and 2R1 = R2 = R3
Solution
Using KVL, in ABCDEFA, we get
- iR1 + V2 - iR3 + V1 = 0
⇒ i =
Using KVL in ABCDA,
0 + V1 - iR1 = 0 ⇒ i =
⇒
⇒ V1R1 + V1R3 = V1R1 + V2R1
⇒
Now possible answers are A, B, D.
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