JEE Main | 2018Set, Relation and FunctionEasy
Question
Two sets A and B are as under
A = {(a, b) R R : |a - 5| < 1 and
|b - 5| < 1};
B = {(a, b)R R : 4(a - 6)2 + 9(b - 5)2 36}.
Then :-
Options
A.
A B
B.
A (an empty set)
C.
neither A B nor B A
D.
B A
Solution

A = {(a, b) : |a - 5| < 1, |b - 5| < 1}
Let a - 5 = x, b - 5 = y
Set A contains all points inside |x| < 1, |y| < 1
B = {(a, b) : 4(a - 6)2 + 9(b - 5)2 36}
Set B contains all points inside or on
lies inside the ellipse
Create a free account to view solution
View Solution FreeMore Set, Relation and Function Questions
If the two roots of the equation, (a − 1)(x4 + x2 + 1) + (a + 1)(x2 + x + 1)2 = 0 are real and distinct, then the ...Let f:R → , where f(x) = tan-1 , then-...Let f: (-1, 1) → R be a differentiable function with f(0) = - 1 and f′(0) = 1. Let g(x) = [f(2f(x) + 2)]2. T...In a class of 100 students, 55 students have passed in Mathematics and 67 students have passed in physics, no student fa...If A = {1, 2, 3}, B = {1, 4, 6, 9} and R is a relation from A to B defined by ′x is greater than y′. The ran...