JEE Main | 2018Quadratic EquationHard

Question

Let g(x) = cos x2, f(x) = x and α, β (α<β) be the roots of the quadratic equation 18x2 - 9πx + π2 = 0. Then the area (in sq. units) bounded by the curve y = (gof) (x) and the lines x = α, x =β and y = 0 is -

Options

A.

12(3+1)

B.

12(3-2)

C.

12(2-1)

D.

12(3-1)

Solution

18x2 - 9πx + π2 = 0     ;      gof(x) = cosx
(3x - π) (6x - π) = 0
α=π6, β=π3
A = ∫π/6π/3cosx dx
A = 3-12

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