Question

Let g(x) = cos x², f(x) = $\sqrt{x}$ and $\alpha , \beta (\alpha <\beta )$ be the roots of the quadratic equation 18x² - 9$\pi$x + $\pi$² = 0. Then the area (in sq. units) bounded by the curve y = (gof) (x) and the lines x = $\alpha , x =\beta$ and y = 0 is -