JEE Main | 2018Work, Power and EnergyHard
Question
In a collinear collision, a particle with an initial speed v0 strikes a stationary particle of the same mass. If the final total kinetic energy is 50 % greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after collision, is :
Options
A.
B.
C.
D.
Solution
initial
...(1)
from momentum conservation
mv0 = m(v1 + v2) ...(2)
(v1 + v2)2 = v02
(v1 - v2)2 =
v1 - v2 =
Create a free account to view solution
View Solution FreeMore Work, Power and Energy Questions
A sphere of mass m moving with a constant velocity collides with another stationary sphere of same mass. The ratio of ve...A body of 2 kg mass is moving under a force. The relation between time and displacement is x = where x is in meter and t...A block of mass 0.50 kg is moving with a speed of 2.00 m/s on a smooth surface. It strikes another mass of 1.00 kg and t...The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This ind...A particle moves in a circular path of radius R. If Fc and Ft are the centripetal and tangential forces acting on the pa...