JEE Main | 2018Laws of MotionHard

Question

A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 1012/sec. What is the force constant of the bonds connecting one atom with the other ? (Mole wt. of silver =108 and Avagadro number = 6.02 × 1023 gm mole-1)

Options

A.

7.1 N/m

B.

2.2 N/m

C.

5.5 N/m

D.

6.4 N/m

Solution

Time period of SHM is given by
T = 2πmk
frequency = 12πkm=1012
where m = mass of one atom
=1086.02×1023×10-3kg
12πk108×10-3×6.02×1023=1012
On solving K = 7.1 N/m

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