Laws of MotionHard
Question
System shown in figure is in equilibrium. The magnitude of change in tension in the spring just before and just after, when one of the spring is cut. Mass of both the blocks is same and equal to m and spring constant of both springs is k. (Neglect any effect of rotation)
Options
A.
B.
C.
D.
Solution
2T1 = 2 mg
After cutting the spring
T2 = 2 mg
T2 − T1 = 2 mg −
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
The rear side of a truck is open and a box of mass 20 kg is placed on the truck 4m away from the open end, μ = 0.15...A light spring balance hangs from the hook of the other light spring balance and a block of mass M kg hangs from the for...Two masses m2 = 10 kg and m1 = 5kg are connected by a string passing over a pulley as shown. If the coefficient of frict...There are two identical small holes of area of cross section a on the opposite sides of a tank containing a liquid of de...Two blocks with masses 100 g and 200 g are attached to the ends of springs A and B as shown in figure. The energy stored...