NEET | 2016Chemical BondingHard

Question

The correct thermodynamic conditions for the spontaneous reaction at all temperatures is:

Options

A.

∆H < 0 and ∆S = 0

B.

∆H > 0 and ∆S < 0

C.

∆H < 0 and ∆S > 0

D.

∆H < 0 and ∆S < 0

Solution

∆G = ∆H - T∆S
Spontaneous at all temperature ∆H < 0, ∆S > 0

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