Chemical BondingHard

Question

Which of the following statements is/are correct ?
Commercial HCl is prepared by heating NaCl with H2SO4.
2NaCl + H2SO4 →  N2SO4 + 2HCl

Options

A.196.0 g of pure H2SO4 is required for thr production of 245.0 g of cone HCl containing 40% HCl by weight
B.245.0 g of 80% H2SO4 by weight is required for the production of 365.0 g of cone. HCl containing 40% HCl by weight.
C.2 mol of pure H2SO4 is required for the production of 365 g of 40% HCl.
D.2.5 mol of 80% H2SO4 is required for the production of 365.0 g of 40% HCl.

Solution

a.    Weight of 40% HCl = × 36.5 = 146 g
2 mol HCl (2 × 36.5 = 73 g) = 1 mol H2SO4 (98g)
Weight of H2SO4 = (146 g HCl)
= 196 g H2SO4.
b.    Weight of 80% H2SO4
= = 245 g H2SO4
c.    Mole of pure H2SO4
= = 2 mol H2SO4
d.     Mole of 80% H2SO4 = = 2.5 mol H2SO4

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