A small signal voltage V(t) = V0 sin ωt is applied across an ideal capacitor C:

NEET | 2016Current Electricity and Electrical InstrumentHard

Question

A small signal voltage V(t) = V₀ sin $ω$ t is applied across an ideal capacitor C:

Current I(t), legs voltage V(t) by 90^o

Over a full cycle the capacitor C does not consume any energy from the voltage source

Current I(t) is in phase with voltage V(t).

Current I(t) leads voltage V(t) by 180^o

In capacitor current leads the voltage. Average power dissipated in capacitor is zero

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