NEET | 2016SemiconductorEasy

Question

A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of800 Ω is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplificationfactor is 0.96 and the input resistance of the circuit is 192 Ω, the voltage gain and the power gain of theamplifier will respectively be:

Options

A.

4, 3.84

B.

3.69, 3.84

C.

4, 4

D.

4, 3.69

Solution

Voltage gain = β. RCRB
V = 0.96 80192
V=96×8192=4
And power gain of the amplifier is
βac.Av
= 0.96 ×4
= 3.84

Create a free account to view solution

View Solution Free
Topic: Semiconductor·Practice all Semiconductor questions

More Semiconductor Questions

For p - type semiconductor impurity element is : -...The real time variation of input singles A and B are as shown below. If the inputs are fed into NAND gate, then select t...For pure ″Ge″ semiconductor quantity of ″e″ and hole pair is 1019 e/m3 if we doped donor impurit...When added an impurity into the silicon which one of the following produces n-type of semi-conductors:...Electric conduction in a semi-conductor takes place due to :-...