Current Electricity and Electrical InstrumentHard

Question

A 100 V, 50 Hz A.C. supply is connected to a series L-R circuit. The current in the circuit is 5A and the average power dissipated is 100W the value of R is :-

Options

A.5 Ω
B.4 Ω
C.1 Ω
D.2 Ω

Solution

P = I2R
100 = (5)2R
R = 4Ω

Create a free account to view solution

View Solution Free
Topic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions

More Current Electricity and Electrical Instrument Questions