JEE Main | 2014Trigonometric EquationHard
Question
Let fk(x) =
(sink x + cosk x) where x ∈ R and k ≥ 1.
Then f4(x) - f6(x) equals
(sink x + cosk x) where x ∈ R and k ≥ 1. Then f4(x) - f6(x) equals
Options
A.

B.

C.

D.

Solution
fk(x) =
(sink x + cosk x)
f4(x) - f6(x) =
(sin4x + cos4x) -
(sin6x + cos6x)
=
[1 - 2 sin2 x cos2 x] -
[1 - 3 sin2 x cos2x]

(sink x + cosk x)f4(x) - f6(x) =
(sin4x + cos4x) -
(sin6x + cos6x)=
[1 - 2 sin2 x cos2 x] -
[1 - 3 sin2 x cos2x]
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
The most general values of x for which sin x + cos x = {1, a2 − 4a + 6} are given by -...The angle between the lines whose direction consines satisfy the equations l + m + n = 0 and l2 = m2 + n2 is...If a1, a2, a3 ..... an be in A.P. , (1 + sin 2θ) is arithmetic mean of a1, an , (1 - tan θ)is arithmetic mean ...If a = sin 170o + cos 170o, then -...Match List-I with List-II and select the correct answer using the code given below the lists....