NEET | 2017Chemical BondingHard

Question

Pick out the correct statement with respect to [Mn(CN)₆]³Â–:-

Options

A.

It is sp³d² hybridised and tetrahedral

B.

It is d²sp³ hybridised and octahedral

C.

It is dsp² hybridised and square planar

D.

It is sp³d² hybridised and octahedral

Solution

[Mn(CN)₆]^3- $\to$ O.S. of Mn is (+3)
$C . N . = 6$
Mn⁺³ $\to$ 3d⁴ $\to$
Presence of SFL (Pairing is possible)
[d²sp³, octahedral]
t₂g eg

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