SHMHard
Question
A simple pendulum of length 1 m is allowed to oscillated with amplitude 2o. It collides elastically with a wall inclined at 1o to the vertical. Its time period will be : (use g = π2)
Options
A.2/3 sec
B.4/3 sec
C.2 sec
D.None of these
Solution
Time period for half part : T = 
= 2sec.
So 2o part will be cornered in a time t =
= 1 sec.
For the left 1o part : θ = θ0 sin (ωt)1o = 2o sin
= π × t ⇒ t = 1/6 sec.
Total time =
+ 2t ⇒ 1 + 2 × 
= 1 + 
sec.
= 2sec.So 2o part will be cornered in a time t =
= 1 sec.For the left 1o part : θ = θ0 sin (ωt)1o = 2o sin
= π × t ⇒ t = 1/6 sec.Total time =
+ 2t ⇒ 1 + 2 × = 1 + sec.Create a free account to view solution
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