ElectrostaticsEasy
Question
Two identical thin rings, each of radius R, are coaxially placed a distance R apart, If Q1 and Q2 are respectively the charges uniformally speread on the two rings, the work done in moving a charge q from the centre of one ring to that of the other is
Options
A.zero
B.q(Q1 - Q2) (√2 - 1) / √2(4πε0R)
C.q√2 (Q1 + Q2) / (4πε0R)
D.q(Q1 / Q2) (√2 + 1) √2(4πε0R)
Solution
VC1 = VQ1 + VQ2 =
Similarly VC2 =
∴ ᐃV = VC1 - VC2
W = qᐃV = q(Q1 - Q2)(√2 - 1) /√2(πε0R.)
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