The integral∫2x12+5x9(x5+x3+1)3 dx is equal to :
x102(x5+x3+1)2+c
x52(x5+x3+1)2+c
-x102(x5+x3+1)2=c
-x5(x5+x3+1)2=c
I2x3+5x61+1x2+1x53dx,   let 1+1x2+1x5=t Hence I=x102x5+x3+12+c
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