CircleHard

Question

The circle described on the line joining the points (0, 1), (a, b) as diameter cuts the x-axis in points whose abscissa are roots of the equation:

Options

A. x² + ax + b = 0
B. x² - ax + b = 0
C. x² + ax - b = 0
D. x² - ax - b = 0

Solution

Equation of circle (x _ 0) (x _ a) + (y _ 1)(y _ b) = 0

it cuts x-axis put y = 0 Þ x2 _ ax + b = 0

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