CircleHard

Question

If (0, 1) and (1, 1) are end points of a diameter of a circle, then its equation is-

Options

A.x2 + y2 − x − 2y + 1 = 0
B.x2 + y2 + x − 2y + 1 = 0
C.x2 + y2 − x − 2y − 1 = 0
D.None of these

Solution

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