CircleEasy
Question
The circle described on the line joining the points (0, 1), (a, b) as diameter cuts the x-axis in points whose abscissa are roots of the equation:
Options
A. x² + ax + b = 0
B.
x² - ax + b = 0
C.
x² + ax
- b = 0
D. x²
- ax - b = 0
Solution
Equation of circle (x _ 0) (x _ a) + (y _ 1)(y _ b) = 0
it cuts x-axis put y = 0 Þ x2 _ ax + b = 0
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