CircleHard
Question
The circle described on the line joining the points (0, 1), (a, b) as diameter cuts the x-axis in points whose abscissa are roots of the equation:
Options
A. x² + ax + b = 0
B.
x² - ax + b = 0
C.
x² + ax
- b = 0
D. x²
- ax - b = 0
Solution
Equation of circle (x _ 0) (x _ a) + (y _ 1)(y _ b) = 0
it cuts x-axis put y = 0 Þ x2 _ ax + b = 0
Create a free account to view solution
View Solution FreeMore Circle Questions
Equation of line passing through mid point of intercepts made by circle x2 + y2 _ 4x _ 6y = 0 on co-ordinate axes is...If the lines 2x + 3y + 1 = 0 and 3x - y - 4 = 0 lie along diameters of a circle of circumference 10π, then the equa...If the circles x2 + y2 + 2ax + cy + a = 0 and x2 + y2 - 3ax + dy - 1 = 0 intersect in two distinct points P and Q then t...For the equation x2 + y2 + 2λx + 4 = 0 which of the following can be true -...The centres of the circles x2 + y2 _ 6x _ 8y _ 7 = 0 and x2 + y2 _ 4x _ 10y _ 3 = 0 are the ends of the diameter of the ...