JEE Main | 2014Momentum and CollisionHard
Question
On heating water, bubbles being formed at the bottom of the vessel detatch and rise. Take the bubbles to be spheres of radius R and making a circular contact of radius r with the bottom of the vessel. If r << R, and the surface tension of water is T, value of r just before bubbles detatch is (Density of water is ρw)


Options
A.R2
B.

C.

D.

Solution

When the bubble gets detached,
Buoyant force = force due to surface tension
∫ T × dl sin θ =
π R3 ρwg⇒ T × 2πr ×
π R3 ρwg⇒ r2 =

⇒ r = R2

Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, the average t...Two blocks A and B each of mass m, are connected by a massless spring of natural length L and spring constant k. The blo...A smooth sphere is moving on a horizontal surface with a velocity vector $(2\widehat{i} + 2\widehat{j})$ m/s immediately...If a solid sphere of mass 1 kg and radius 0.1 m rolls with out sliping at a uniform velocity of 1 m/s along a straight l...A ball is projected from ground with a velocity V at an angle θ to the vertical. On its path it makes an elastic collisi...