CircleHard

Question

The centres of the circles x2 + y2 _ 6x _ 8y _ 7 = 0 and x2 + y2 _ 4x _ 10y _ 3 = 0 are the ends of the diameter of the circle

Options

A. x2 + y2 _ 5x _ 9y + 26 = 0
B. x2 + y2 + 5x _ 9y + 14 = 0

C. x2 + y2 + 5x _ y _ 14 = 0
D. x2 + y2 + 5x + y + 14 = 0

Solution

(3,4) & (2,5) are ends of diameter of circle

So, Equation (x _ 3)(x _2) + (y _4)(y _5) = 0

x2 + y2 _ 5x _ 9y + 26 = 0

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