JEE Main | 2014Heat and Thermal ExpansionMedium
Question
The pressure that has to be applied to the ends of a steel rod of length 10 cm to keep its length constant when its temperature is raised by 100oC is :
(For steel Young′s modulus is 2 × 1011 Nm-2 and coefficient of thermal expansion is 1.1 × 10-5 K-1)
(For steel Young′s modulus is 2 × 1011 Nm-2 and coefficient of thermal expansion is 1.1 × 10-5 K-1)
Options
A.2.2 × 108 Pa
B.2.2 × 109 Pa
C.2.2 × 107 Pa
D.2.2 × 106 Pa
Solution
As length is constant,
Strain =
= αᐃQ
Now pressure = stress = Y × strain
= 2 × 1011 × 1.1 × 10-5 × 100
= 2.2 × 108 Pa
Strain =
= αᐃQNow pressure = stress = Y × strain
= 2 × 1011 × 1.1 × 10-5 × 100
= 2.2 × 108 Pa
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