CircleEasy
Question
Equation of line passing through mid point of intercepts made by circle x2 + y2 _ 4x _ 6y = 0 on
co-ordinate axes is
Options
A. 3x + 2y _ 12 = 0
B. 3x + y _ 6 = 0
C. 3x + 4y _ 12 = 0
D. 3x + 2y _ 6 = 0
Solution
given circle
x2 + y2 _ 4x _ 6y = 0
it cuts x-axis put y = 0, x = 0, 4
it cuts y-axis put x = 0, y = 0, 6
Hence mid points on x-axis (2, 0)
on y-axis (0, 3)
Equations of line 
= 1 Þ 3x + 2y _ 6 = 0
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