JEE AdvancedCircleHard

Question

The x coordinates of two points A and B are roots of equation x2 + 2x − a2 = 0 and y coordinate are roots of equation y2 + 4y − b2 = 0 then equation of the circle which has diameter AB is-

Options

A.(x − 1)2 + (y − 2)2 = 5 + a2 + b2
B.(x + 1)2 + (y + 2)2 =
C.(x + 1)2 + (y + 2)2 = (a2 + b2)
D.(x + 1)2 + (y + 2)2 = 5 + a2 + b2

Solution

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