JEE Main | 2014Rotational MotionHard
Question
A mass m is supported by a massless string wound around a uniform hollow cylinder of mass m and radius R. If the string does not slip on the cylinder, with what acceleration will the mass fall on release?


Options
A.

B.

C.

D.g
Solution

a = Rα
mg - T = ma
T × R = mR2α
or T = ma
⇒ a =

Create a free account to view solution
View Solution FreeMore Rotational Motion Questions
Two rings of the same radius and mass are placed such that their centers are at a common point and their planes are perp...A bicycle is in motion. The force of friction exerted by the ground on its wheel is such that it acts :...Two solid spheres are made of the same material. The ratio of their diameters in 1 : 2. The ratio of their moments of in...The linear and angular acceleration of a particle are 10 m/sec2 and 5 rad/sec2 respectively. It will be at a distance fr...A rod of mass M and length L is placed in a horizontal plane with one end hinged about the vertical axis. A horizontal f...