JEE Main | 2014Rotational MotionEasy
Question
A mass m is supported by a massless string wound around a uniform hollow cylinder of mass m and radius R. If the string does not slip on the cylinder, with what acceleration will the mass fall on release?
Options
A.
B.
C.
D.g
Solution
a = Rα
mg - T = ma
T × R = mR2α
or T = ma
⇒ a =
Create a free account to view solution
View Solution FreeMore Rotational Motion Questions
A particle of mass 5 kg. and moment of inertia 2 kg-m2 is revolving with angular acceleration of 30 rad./s2. If particle...A particle of mass m is projected with a velocity v making an angle of 45o with the horizontal. The magnitude of the ang...A phonograph turn-table rotating at 78 rev/min slows down and stops in 30 sec after the motor in turned off. Then the re...A fan of moment of inertia 0.6 kg × metre2 is to run upto a working speed of 0.5 revolution per second. Indicate th...A stone is tied to a string and is rotated round the finger and is then released. The string wrapps around the finger, t...