JEE Main | 2014KinematicsHard

Question

From a tower of height H, a particle is thrown vertically upwards with a speed u. The time taken by the particle, to hit the ground, is n times that taken by it to reach the highest point of its path. The relation between H, u and n is:

Options

A.2gH = n2u2
B.gH = (n - 2)2u2
C.2gH = nu2 (n - 2)
D.gH = (n - 2)u2

Solution

       
Time taken to reach highest point is t1 =
Speed on reaching ground =
Now, v = u + at
⇒     = - u + gt
⇒    
⇒     2gH = n(n - 2)u2

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