SHMHard
Question
The time period of a particle in simple harmonic motion is T. A time T/6 after it passes its mean position, its:
Options
A.velocity will be one half its maximum velocity
B.displacement will be one half of its amplitude
C.acceleration will be nearly 86% of its maximum acceleration
D.KE = PE
Solution
V = V0 cos ωt = V0 cos 
at t =
V = V0 cos
(A)
a = a0 sin ωt = a0 sin
t =
a = a0 sin
= 0.86 a0 (C)
at t =
V = V0 cos
(A)a = a0 sin ωt = a0 sin
t =
a = a0 sin
= 0.86 a0 (C)Create a free account to view solution
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