SHMMedium

Question

A particle  excites S.H.M. in a straight line. line In the first second starting from rest it travels a distance ′a′ and in the next second a distance ′b′ in the same direction . The amplitude of S.H.M will be

Options

A.
B.a - b
C.2a - b
D.a / b

Solution


x = Acosωt ⇒ a = Acosω and a + b = Acos 2ω
⇒ a + b = A[2cos2ω - 1] = A
⇒ - A = a + b ⇒ A2 + (a + b)A - 2a2 = 0
⇒ A =
Note : Please correct the answer of the question 

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