SHMHard
Question
A 25 kg uniform solid sphere with a 20 cm radius is suspended by a vertical wire such that the point of suspension is vertically above the centre of the sphere. A torque of 0.10 N-m is required to rotate the sphere through an angle of 1.0 rad and then maintain the orientation. If the sphere is then released, its time period of the oscillation will be :
Options
A.π-second
B.√2π-second
C.2π-second
D.4π-second
Solution
I = I = 
mR2 = 
× 25 × (0.2)2 = 
t = Cθ c =
= 0.1
T = 2π
= 2π × 2 = 4π secs
mg src="uploads/1440133880.JPG" align="middle"> mR2 = × 25 × (0.2)2 =
t = Cθ c = = 0.1
mR2 = × 25 × (0.2)2 = t = Cθ c =
= 0.1T = 2π
= 2π × 2 = 4π secs × 25 × (0.2)2 = t = Cθ c =
= 0.1Create a free account to view solution
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